(2z-1)=(3z^2+1)

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Solution for (2z-1)=(3z^2+1) equation: 



(2z-1)=(3z^2+1)

We move all terms to the left:

(2z-1)-((3z^2+1))=0

We get rid of parentheses

2z-((3z^2+1))-1=0



We calculate terms in parentheses: -((3z^2+1)), so:

(3z^2+1)

We get rid of parentheses

3z^2+1

Back to the equation:

-(3z^2+1)



We get rid of parentheses

-3z^2+2z-1-1=0

We add all the numbers together, and all the variables

-3z^2+2z-2=0

a = -3; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·(-3)·(-2)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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